Respuesta :
a) 252/98Cf & 10/5 B ==> 3 1/0n & 259/103 Lr
b) 2/1H & 3/2He ===> 4/2He & 1/1 H
c) 1/1H & 11/5B => 3 4/2He
d) 122/53 I ==> 122/54 Xe & 0/-1e- (Beta)
e) 59/26Fe ==> 0/-1e & 59/27 Co
b) 2/1H & 3/2He ===> 4/2He & 1/1 H
c) 1/1H & 11/5B => 3 4/2He
d) 122/53 I ==> 122/54 Xe & 0/-1e- (Beta)
e) 59/26Fe ==> 0/-1e & 59/27 Co
Answer: The equations are given below.
Explanation:
- For a:
[tex]^{252}_{98}\textrm{Cf}+^{10}_5\textrm{B}\rightarrow ^A_Z\textrm{X}+3^{1}_{0}\textrm{n}[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
252 + 10 = A + 3
A = 259
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
98 + 5 = Z + 0
Z = 103
The isotopic symbol of lawrencium is [tex]_{103}^{259}\textrm{Lr}[/tex]
- For b:
[tex]^{2}_{1}\textrm{H}+^{3}_2\textrm{He}\rightarrow ^4_2\textrm{He}+^A_{Z}\textrm{X}[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
2 + 3 = A + 4
A = 1
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
1 + 2 = Z + 2
Z = 1
The isotopic symbol of hydrogen is [tex]_{1}^{1}\textrm{H}[/tex]
- For c:
[tex]^{1}_{1}\textrm{H}+^{11}_5\textrm{B}\rightarrow 3^A_{Z}\textrm{X}[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
1 + 11 = A
A = 12
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
1 + 5 = Z
Z = 6
The isotopic symbol of helium is [tex]_{2}^{4}\textrm{He}[/tex]
- For d:
[tex]^{122}_{53}\textrm{I}\rightarrow ^{122}_{54}\textrm{Xe}+_Z^A\textrm{X}[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
122 = A
A = 122
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
53 = 54 + Z
Z = -1
The isotopic symbol of electron is [tex]_{-1}^{0}\textrm{e}[/tex]
- For e:
[tex]^{59}_{26}\textrm{Fe}\rightarrow ^{0}_{-1}\textrm{e}+_Z^A\textrm{X}[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
59 + 0 = A
A = 59
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
26 = -1 + Z
Z = 27
The isotopic symbol of Cobalt is [tex]_{27}^{59}\textrm{Co}[/tex]