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A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Respuesta :

pkmnmushy
This can easily be answered. Justg use the next formula like this:
0.4*0.05 = 0.02 
So the probability would be of 2% of both shots
Hpe this is very useful

Answer:

[tex]0.2[/tex] %

Step-by-step explanation:

Chance of missing the first shot is [tex]0.4\\[/tex]

Chance of missing the second shot, when the first shot is missed is [tex]0.05\\[/tex]

The probability of missing both free-throw shots

[tex]= (0.4) (0.05)\\= 0.002\\= 0.2[/tex] %

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