Our first function is g(x). Al had two dozen donuts means that two dozen is the y-intercept of this function. A dozen equals 12, therefore two dozens is 24. Every cubicle he passed, he lost 2 donuts is the slope of the function and it is negative, that is -2, thus:
[tex]g(x)=-2x+24 \\ \\ \boxed{y-intercept = 24}[/tex]
The second equation is h(x):
[tex]h(x)=6x+1[/tex]
So:
[tex]\boxed{y-intercept=1}[/tex]
From the graph, we can see that the f(x) intersects the y-axis at:
[tex]\boxed{y-intercept=2}[/tex]
Accordingly, h(x) has the lowest y intercept.
In conclusion, the right answer is c.h(x)
