The perimeter of a college athletic field is 96 meters and the length is 14m more thanthe width. find the width and length

set x = length, then x-14 would be width,
perimeter would be 2(x) + 2(x-14) = 96,
simplify this, u get 2x + 2x - 28 = 96,
you then get 4x = 124, now we know x = 31,
you would then be 31-14 which is 17.
so length is 31 m and width is 17 m

Answer Link

JeanaShupp JeanaShupp · Answer 2 · 2019-08-23T21:13:51+02:00

Answer: Width = 17 meters , length = 31 meters

Step-by-step explanation:

Given : The perimeter of a college athletic field is 96 meters and the length is 14m more than the width.

Let the width of the college athletic field be x.

Then , the length of the college athletic field e will be x+14.

The formula to find the perimeter of rectangle is given by :-

[tex]\text{Perimeter}=2(l+b)[/tex]

i.e. [tex]96=2(14+x+x)[/tex]

[tex]\Rightarrow\ \dfrac{96}{2}=(14+2x)[/tex]

[tex]\Rightarrow\ 48=14+2x[/tex]

[tex]\Rightarrow\ 2x=48-14=34\\\\\Rightarrow\ x=\dfrac{34}{2}=17[/tex]

Hence, the width of the college athletic field = 17 meters

and the length of the college athletic field = [tex]17+14=31\text{ meters}[/tex]