The probability that one of the three horses finishes first is 3/11. If one of the three horses has finished first, then the probability that one of the remaining two horses finishes second is 2/10. If two of the three horses have finished first and second, then the probability of the remaining horse from the three finishing third is 1/9. Therefore the required probability is given by:
3 x 2 x 1/11x 10 x 9= you can calculate
