A 1.0 mL volume of 0.010 M H2SO4 is added to a mixture of 6 drops of 0.010 M HIO3, 14 drops of deionized water, and 1 drop of starch solution. A color change in the reaction mixture occurred after 56 seconds. a.) Assuming 20 drops per milliliter for all solutions, determine the initial molar concentration of HIO3 after the mixing but before any reaction occurs (at time = 0). b. )The rate of the reaction is measured by the disappearance of HIO3. For the reaction mixture in this question, what is the reaction rate? Express the reaction rate in units of mol HIO3/L / sec to correct sig. figs.

Respuesta :

We have that the initial molar concentration of HIO3  is mathematically given as

CHl0_3 = 2.6 x10^3M

Concentration

Generally the equation for the Volume starch  is mathematically given as

Volume of starch = 1 /25 x 1

Volume of starch= 0.04 mL

Therefore

Total volume of solution

Vs=1.0+0.48 0.32. 0.04

Vs=1.84 mL

Vs= 0.00184 L

Moles of Hl0_3 = stock volume x stock concentration Hl0_3

[tex]MHl0_3 = 0.48/1000 x 0.010 = 0.8x 106 mol[/tex]

Initial concentration of H1l03 = moles of H103/total volume

[tex]CHl0_3 = 4.8 x 104/0.00184 \\\\CHl0_3 = 0.00261M[/tex]

CHl0_3 = 2.6 x10^3M

For more information on Volume visit

https://brainly.com/question/1578538