We have that the initial molar concentration of HIO3 is mathematically given as
CHl0_3 = 2.6 x10^3M
Generally the equation for the Volume starch is mathematically given as
Volume of starch = 1 /25 x 1
Volume of starch= 0.04 mL
Therefore
Total volume of solution
Vs=1.0+0.48 0.32. 0.04
Vs=1.84 mL
Vs= 0.00184 L
Moles of Hl0_3 = stock volume x stock concentration Hl0_3
[tex]MHl0_3 = 0.48/1000 x 0.010 = 0.8x 106 mol[/tex]
Initial concentration of H1l03 = moles of H103/total volume
[tex]CHl0_3 = 4.8 x 104/0.00184 \\\\CHl0_3 = 0.00261M[/tex]
CHl0_3 = 2.6 x10^3M
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