Answer:
(a) Resistance will be 2500 ohm
(b) Inductance will be 0 Henry
Explanation:
We have given emf of the battery V = 12 volt
Current at time t = 0.745 sec is 4.80 mA
After a long time current is 6.40 mA
After a long time means time tends to infinite
At infinite time inductor behaves as short circuit, so there is only resistance in the circuit
So resistance [tex]R=\frac{V}{i}=\frac{12}{4.8\times 10^{-3}}=2500ohm[/tex]
Current at time in inductive circuit is given by
[tex]i=\frac{V}{R}e^\frac{-t}{\tau }[/tex]
[tex]4.8\times 10^{-3}=\frac{12}{2500}e^\frac{-0.745\times 10^{-3}}{\tau }[/tex]
[tex]e^\frac{-0.745\times 10^{-3}}{\tau }=1[/tex]
[tex]\frac{-0.745\times 10^{-3}}{\tau }=ln1[/tex]
[tex]\tau =0sec[/tex]
[tex]\tau =\frac{L}{R}[/tex]
L = 0 Henry
