Answer : The molality of sugar solution is, 0.04038 mole/Kg
Solution : Given,
Mass of solute (sucrose) = 3.94 g
Mass of solvent (water) = 285 g
Molar mass of sucrose = 342.3 g/mole
Molality : It is defined as the number of moles of solute present in one kilogram of solvent.
Formula used :
[tex]Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent in g}}=\frac{3.94g\times 1000}{342.3g/mole\times 285g}=0.04038mole/Kg[/tex]
Therefore, the molality of sugar solution is, 0.04038 mole/Kg
