Respuesta :

nobillionaireNobley
a1 = 2
a2 = 2(4) = 8
a3 = 2(4)^2 = 2(16) = 32
a4 = 2(4)^3 = 2(64) = 128
a5 = 2(4)^4 = 2(256) = 512
a6 = 2(4)^5 = 2(1024) = 2,048
Parrain

The first six terms of a sequence where a₁ = 2 and r = 4 are:

  • a₁ = 2
  • a₂ = 8
  • a₃ = 32
  • a₄ = 128
  • a₅ = 512
  • a₆ = 2,048

How can the sequence be graphed?

The first term is:

a₁ = 2

r will then multiply the first term and then be increased by succeeding powers.

an = 2 (r) ^(n - 1)

a₂ = 2 (4) = 8

a₃ = 2 (4)² = 32

a₄ = 2 (4)³ = 128

a₅ = 2 (4)⁴ = 512

a₆ = 2 (4)⁵ = 2,048

Find out more on expanding sequences at https://brainly.com/question/20886273.

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