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A bag is dropped from a hovering helicopter. When the bag has fallen 2 seconds,
a. What is the bag's velocity?
b. How far has the bag fallen?

Respuesta :

a) Vt = Vo - gt
= 0 - 9.8 . 2
= - 19.6 m/sec (acting downward)
b) ∆y = Vt^2 - Vo^2 / 2g
= (-19.6)^2 - 0 / 19.6 = 19.6 meters

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