Answer:
y = -[tex]\frac{1}{3}[/tex] + 4
Step-by-step explanation:
first of all we know the slope of the equation which is 3x. then we know that we are supposed to write an equation that is perpendicular to y = 3x + 3. so since it is supposed to be perpendicular we have to make the current slope opposite.
so slope for our new equation will be -[tex]\frac{1}{3}[/tex]x.
now since we know our slope we use point-slope form and plug everything in.
point-slope form: y1-y=m(x1-x)
plug it in:
y - 2 = -[tex]\frac{1}{3}[/tex] (x - 6)
= y - 2 = -[tex]\frac{1}{3}[/tex]x +2
= y = -[tex]\frac{1}{3}[/tex] + 4
