Answer:
[tex]x=55[/tex]
Step-by-step explanation:
To solve this question you need to know some properties of a parallelogram which is the shape given.
Firstly, remember that in a parallelogram opposite angles are equal.
Secondly, remember that the diagonals of a parallelogram bisect each other.
Lastly, remember that the sum of the interior angles of a quadrilateral or a parallelogram is 360°.
So, by using the first property we can see that because [tex]<[/tex]PQR=70° then [tex]<[/tex]PSR must be equal to 70° as well.
Now, we can use the last property to find [tex]<[/tex]SPQ then, use the second property to find [tex]x[/tex].
Let's name [tex]<[/tex]SPQ, [tex]y[/tex].
and That gives:
[tex]2y+140=360[/tex]
Subtract 140 from both sides:
[tex]2y=360-140[/tex]
[tex]2y=220[/tex]
[tex]y=\frac{220}{2}[/tex]
[tex]y=110[/tex]
So, [tex]<[/tex]SPQ=110 and
Now using the second property we can find that:
[tex]<[/tex]SPQ=[tex]2x[/tex]
And [tex]2x=110[/tex]
[tex]x=\frac{110}{2}[/tex]
[tex]x=55[/tex]
Hope this helped.
