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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B.

How fast did Car A travel?

(The formula Râ‹…T=D , where R is the rate of speed, T is the time, and D is the distance can be used.)

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nicks1324

Answer:

We let x the distance traveled by Car A and y the distance traveled by car B. The speed of car A can be represented as x/2.4 and for Car B is y/4. From the statement given, we can write an equation relating the speed of both cars.

x/2.4 = 22 + y/4

Since y = x, then:

x/2.4 = 22 + x/4

Solving for x, we obtain:

x= 132 meters traveled by both cars

Therefore, Car A has a speed of 55 mph.

Step-by-step explanation:

Answer:

Step-by-step explanation:

x/2.4 = 22 + y/4

Since y = x, then:

x/2.4 = 22 + x/4

x= 132 meters traveled by both cars

Therefore, Car A has a speed of 55 mph.

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