Directions: Find the specified term of the geometric sequences given the first term and the common ratio.

Step-by-step explanation:
As you know
[tex] a_{n} = a_{1} \times {r}^{n - 1} [/tex]
1.
[tex]3 \times {3}^{4} = {3}^{5} \\ 3 \times {3}^{6} = {3}^{7} \\ 3 \times {3}^{8} = {3}^{9}[/tex]
2.
[tex]2 \times {2}^{4} = {2}^{5} \\ 2 \times {2}^{6} = {2}^{7} \\ 2 \times {2}^{8} = {2}^{9}[/tex]
3.
[tex] - \frac{1}{2} \times {( - 6)}^{4} = { \frac{ - 1}{2} } \times {6}^{4} \\ - \frac{1}{2} \times {( - 6)}^{6} = { \frac{ - 1}{2} } \times {6}^{6} \\ - \frac{ 1}{2} \times {( - 6)}^{8} = { \frac{ - 1}{2} } \times {6}^{8} [/tex]