12. A 10 mH inductor and a 100 a resistor are connected in parallel. The circuit is supplied with 24 VAC

2,000 Hz. What's the impedance (rounded) of the circuit?

A. 57.382

B. 108.7122

C. 78.23 22

D. 98.16 22

Respuesta :

The impedance of the given AC circuit containing resistor and inductor parallel to each other is 55.71 ohms.

The given parameters;

  • inductance of the inductor, L = 10 mH
  • resistance of the resistor, R = 100 ohms

The inductive reactance is calculated as follows;

[tex]\omega _l = 2\pi fl\\\\\omega _l = 2\times 3.142 \times 2,000\times 10\times 10^{-3} = 125.68 \ ohms[/tex]

The impedance is the total opposition to the flow of current in the AC circuit and it is calculated as follows;

[tex]Z _{total} = \frac{1}{\frac{1}{Z_l} + \frac{1}{Z_R} } \\\\Z _{total} = \frac{1}{\frac{1}{125.68} + \frac{1}{100} }\\\\Z _{total} = 55.71 \ ohms[/tex]

Thus, the impedance of the given circuit is 55.71 ohms.

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