Respuesta :
A food supply company produces Yellow-42 (from previous example) in 200-gram wholesale bottles. The grams of FeCl3 needed to produce one bottle of Yellow 42 is 303.638 grams. Â The amount of NaOH needed to produce one bottle of Yellow 42 is 226.32 grams.
- The mass amount of Yellow 42 = 200 grams
- The molar mass of Fe(OH)3 needed to produce 1 bottle of Yellow 42 = 106.845 g/mol
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Using the relation for the number of moles which is:
[tex]\mathbf{number \ of \ moles = \dfrac{mass }{molar \ mass}}[/tex]
[tex]\mathbf{number \ of \ moles \ of \ Yellow \ 42 = \dfrac{200 g }{106.867 \ g/mol}}[/tex]
[tex]\mathbf{number \ of \ moles \ of \ Yellow \ 42 =1.872 \ moles}[/tex]
Now,
- If 1 mole of Fe(OH)â requires 1 mole of FeClâ
- 1.872 moles of Fe(OH)â will require 1.872 moles of FeClâ
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Mass of FeClâ required = number of moles of  FeClâ Ă molar mass of FeClâ
Mass of FeClâ required = 1.872 moles Ă 162.2 g/mol
Mass of FeClâ required = 303.638 grams
7.
Recall that:
- 1 bottle of the yellow requires 1.872 moles of the Fe(OH)â
- Thus, 1 mole of Fe(OH)â requires 3 moles of NaOH
Now, 1.872 moles of Fe(OH)â will require (3 Ă 1.872 moles of NaOH)
= 5.616 moles of NaOH
Thus, the amount of NaOH in grams, that will be needed to produce one bottle of Yellow 42 is:
= 5.616 moles Ă 40.3 g/mol (molar mass of NaOH)
= 226.32 grams of NaOH
8.
The company could set up this reaction in a way that ensures no iron (III) chloride is wasted in the reaction by using the concept of the stoichiometry of the reaction involved in the system and he should feed the reactant within the ratio of 1:3 for FeClâ and NaOH respectively.
Learn more about stoichiometry here:
https://brainly.com/question/9743981?referrer=searchResults