Answer:
Step-by-step explanation: I am trying to interpret the question: I'll assume:
Line AB has a midpoint, M.
A is (8,4)
B is unknown, but desired
M is (3,-2)
We'll assume a straight line of the form y=mx+b, where m is the slope. m can be calculated by the "Rise" over the "Run" between the points A and M:
Rise = (4-(-2))=6
Run = (8-3)=5
Slope = (Rise/Run) = (6/5)
The line becomes y=(6/5)x+b
Calculate b, the y-intercept (the value of y when x is 0), by entering one of the two known points. I'll choose (8,4).
y=(6/5)x+b
4 = (6/5)(8)+b
b = 4 - (6/5)(8)
b = 4 - (48/5)
b = 4 - (9 3/5) or -5 3/5
The equation becomes:
y=(6/5)x - 5 3/5
Point B will have an x value of -2 [The change in x from A to M was (3-8) = -5. From M to 5 would be another -5 increment, so x goes from 3 to (3-5) or -2.
Find the value of y for x=-2:
y=(6/5)x - 5 3/5
y=(6/5)*(-2) - 5 3/5
y=(-12/5) - (28/5)
y = -(40/5) or - 8
B has coordinates of (-2, -8)
