contestada

A ball is thrown upward with an initial velocity of 22.0 m/s. If
the gravitational acceleration is –9.81 meters per second
squared, what is the maximum height the ball will reach?
Select one:
2.24 m.

24.7 m.


4.48 m.


49.4 m.

Respuesta :

onyebuchinnaji

The maximum height reached by the ball during the upward motion  is 24.7 m.

The given parameters;

  • initial velocity of the ball, u = 22 m/s

The maximum height reached by the ball is determined using the third kinematic equation as shown below;

v² = u² - 2gh

where;

  • v is the final velocity of the ball at the maximum height = 0
  • h is the maximum height attained by the ball

0 = u² - 2gh

2gh = u²

[tex]h = \frac{u^2}{2g} \\\\h = \frac{22^2}{2(9.8)} \\\\h = 24.7 \ m[/tex]

Thus, the maximum height reached by the ball during the upward motion  is 24.7 m.

Learn more here:https://brainly.com/question/24666225

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