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3
Question 2 (1 point)
The frequency of color blindness (dyschromatopsia) in the Caucasian American male
population is estimated to be about 8%. Let's call X the number of color-blind
individuals in a random sample of 8 Caucasian American males. The table gives the
probability distribution for X.
3
What is the mean of this distribution?
0
1
2
3
4
Х
P(X)
טן ס
0.513
0.357
0.109
0.019
0.002
2

Respuesta :

Using the mean concept, it is found that the mean of the distribution is of 0.64.

The mean of a probability distribution is given by the sum of each outcome multiplied by it's probability.

In this problem, the probability of each outcome is given by:

[tex]P(X = 0) = 0.513[/tex]

[tex]P(X = 1) = 0.357[/tex]

[tex]P(X = 2) = 0.109[/tex]

[tex]P(X = 3) = 0.019[/tex]

[tex]P(X = 4) = 0.002[/tex]

The, the mean is:

[tex]E(X) = 0.513(0) + 0.357(1) + 0.109(2) + 0.019(3) + 0.002(4) = 0.64[/tex]

The mean of this distribution is 0.64.

A similar problem is given at https://brainly.com/question/24146527

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