Answer:
D. Yes because the sum of two lengths of any two sides...etc.
This is your answer
Step-by-step explanation:
side1 m = 3
side2 m = 7
2 smaller sides = ( 3 + 7) = 10
10 is larger than 8
proof Pythagoras theorem
3^2 + 7^2 = c^2
sqrt 9 + sqrt 49 = c^2
c^2 = sqrt 58 = 7.6 = 8 rounded to 1 significant figure.
Proof 2
show ratios of each side 3 : 7 : 9
The circumradius of a cyclic polygon is a radius of the circle inside which the polygon can be inscribed. The height can sometimes be such radius but this should be proved from the equation height of a triangle equation
isosceles not using Pythagoras = hᵇ = √ (a² - (0.5
isosceles using Pythagoras= h = 2 * area / b
obtuse height formula =Area of an obtuse-angled triangle = 1/2 × base × height. Therefore, the height of the obtuse triangle can be calculated by: Height = (2 × Area)/base Substituting the values, we get:.
So as we know Given a=3 and c=8, shows a higher amount for 7 but stays 7 in all circumstances of 1significant figure just like 8 stayed rounded down when using round figure just 7. We get;
b = 7.4162
∠α = 22.024° = 22°1'28" = 0.3844 rad
∠β = 67.976° = 67°58'32" = 1.1864 rad
h = 2.78107
area = 11.1243
perimeter = 18.4162
inradius = 1.2081
circumradius = 4
When the circumradius is 4 and we need the ratio to the inradius
this means the ratio is R : r as;
3/4 :7/4 : 8/4 = 18/4 / 7/2 = 9/7 which shows us the cr radius to the in radius ratio.
R:r therefore = 9/7
