Answer:
[tex]\sqrt[3]{\frac{1}{12} }[/tex] * n
Step-by-step explanation:
You want to get the n alone. In order to do that, you need to get rid of the 3rd power. The opposite of a power is a radical. So do:
[tex]\sqrt[3]{\frac{1}{12} }[/tex] * [tex]\sqrt[3]{n^3}[/tex]
This cancels out the n and turns the problem into:
[tex]\sqrt[3]{\frac{1}{12} }[/tex] * [tex]n[/tex]
I can't solve for n since I haven't been given the entire problem (what they're equal to), but you can solve for [tex]\sqrt[3]{\frac{1}{12} }[/tex].
