The value of m in the fourth equation does not tend to zero, hence the function that has a maximum value of m, where m is a positive constant is[tex]f(x)=-(m+x)^2[/tex]: Option D is correct.
For any function to have a maximum, the differential of the function must be equal to zero.
If the functions in options A and B and C are differentiated and equated to zero, the values of m in each function will tend to zero as well.
For the function [tex]f(x)=-(m+x)^2[/tex]
[tex]f'(x) = -2(m+x)\times 1\\f'(x)=-2(m+x)\\0 = m+x\\m = -x[/tex]
Since the value of m in the fourth equation does not tend to zero, hence the function that has a maximum value of m, where m is a positive constant is[tex]f(x)=-(m+x)^2[/tex]
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