Answer:
Explanation:
In the absence of friction, the potential energy at the top of a hill will equal the kinetic energy at the bottom.
Assume that friction is negligible and velocity is essentially zero at the top.
½mv² = mgh
v = √(2gh)
v = √(2(9.8)83)
v = 40.333608...
v = 40 m/s (145 kph)
The maximum velocity of the roller coaster is 40.33m/s
The formula needed to calculate the maximum velocity is expressed as:
[tex]v=\sqrt{2gr} \\[/tex]
g is the acceleration due to gravity
r is the radius
Given the following parameters
mass = 3,320 kg
radius = 83 meters
Substitute the given parameters into the formula:
[tex]v=\sqrt{2(9.8)(83)} \\v=\sqrt{1,626.8}\\v= 40.33m/s[/tex]
Hence the maximum velocity of the roller coaster is 40.33m/s
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