9514 1404 393
Answer:
x=1
Step-by-step explanation:
The function f(x) is undefined where its denominator (x+1) is zero. That will be the case for x=-1.
The composition f(g(x)) will give f(x) an argument of -1 when g(x) = -1. That will be the case when ...
2^x -3 = -1
2^x = 2 . . . . . add 3
x = 1 . . . . . . match exponents
f(g(x)) will have a discontinuity at x = 1.
