Answer:
[tex]y=-2x+2[/tex]
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0).
1) Determine the slope (m)
[tex]m=\displaystyle\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (4, -6) and (0, 2):
[tex]m=\displaystyle\frac{-6-2}{4-0}\\\\m=\displaystyle\frac{-8}{4}\\\\m=-2[/tex]
Therefore, the slope of the line is -2. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-2x+b[/tex]
2) Determine the y-intercept (b)
The y-intercept occurs when x=0. We are given that (0,2) falls on the line, so therefore, 2 is the y-intercept. Plug this into [tex]y=-2x+b[/tex]:
[tex]y=-2x+2[/tex]
I hope this helps!
Answer:
y = - 2x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (4, - 6) and (x₂, y₂ ) = (0, 2 )
m = = = = - 2
The line crosses the x- axis at (0, 2 ) ⇒ c = 2
y = - 2x + 2 ← equation of line
