A 10 kg box initially at rest accelerates uniformly to a speed of 20 m/s in 2 seconds, energy gained by the block 2000 J and Power developed by the box at the end of 10 seconds 5000 Watt
What is work done?
The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force * Displacement
As given in the problem A 10 kg box initially at rest accelerates uniformly to a speed of 20 m/s in 2 seconds
By using the first equation of motion
v = u + at
20 = 0 + 2a
a = 10 m/s²
By using the third equation of motion
v² - u² = 2as
20² - 0² = 2×10×s
s = 400/20
s = 20 m
Force = ma
= 10 ×10
= 100 N
work done = Force × displacement
= 100 ×20
= 2000 J
Velocity after 10 seconds
V= u + at
= 0 + 10×10
= 100 m/s
work done after 10 seconds
= 1/2mv²
= 0.5×10×10²
=50000 J
Power = work done / time
= 50000/10
= 5000 Watt
Thus, energy gained by the block 2000 J and Power developed by the box at the end of 10 seconds 5000 Watt
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