Using the distributive law to factor, the expression becomes 16m + 6n = 2(8m + 3n)
GIven three integers A, B and C, according to the distributive property;
A(B+C) = AB + BC
Given the expression 16m + 6n
First, we need to get the factors of both terms
16m = 2 * 8 * m
6n = 2 * 3 * n
From both factors, we can see that 2 is common to both of them. Hence using the distributive law to factor, the expression becomes;
16m + 6n = 2(8m + 3n)
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