contestada

Which is the equation of the circle that has a diameter with endpoints located at (0, –3) and (6, 5)?
(x – 6)^2 + (y – 5)^2 = 100
(x – 3)^2 + (y – 1)^2 = 25
x^2 + (y + 3)^2 = 100
(x – 5)^2 + y^2 = 25

Respuesta :

adioabiola

The equation of the circle that has a diameter with endpoints located at (0, –3) and (6, 5) is;

  • (x – 3)² + (y – 1)² = 25

The midpoint of the diameter of a circle is it's center.

As such; the coordinates of its center are;

  • x = (0 + 6)

  • x = 3

  • y = (-3 + 5)/2

  • y = 1

The coordinates of the center are then; (3, 1)

The radius of a circle is half the length of the diameter;

  • Radius, r = d/2

  • where; d = √(6-0)² + (5-(-3))²

  • d = √36 + 64

  • d = √100

  • d = 10

Therefore, radius, r = 10/2 = 5.

Therefore, the equation of the circle usually takes the form;

  • (x -f)² + (x -g)² = r²

In this scenario; the equation is;

  • (x – 3)² + (y – 1)² = 25.

Read more;;

https://brainly.com/question/16646649

Otras preguntas