Answer:
B = 3.31662479
rounded to 3.32
Step-by-step explanation:
Pythagorean theorem: [tex]a^{2} + b^{2} = c^{2}[/tex]
A & B = the base and height
C = The diagonal line.
A & B can be base or height. ( base = 2 Height = 3. It can be [tex]2^{2} + 3^{2}[/tex] or [tex]3^{2} + 2^{2}[/tex] )
Because when you add it doesn't matter where each number is put.
I like doing b for the base, because there's a b in base, to make it easier for me. But you can do whatever.
A = 5
B = ?
C = 6
[tex]5^{2} + b^{2} + 6^{2}[/tex]
From here you will solve to get b.
[tex]5*5 + b^{2} = 6 * 6[/tex]
[tex]25 + b^{2} = 36[/tex]
25 - 25 + [tex]b^{2}[/tex] = 36 - 25
[tex]b^{2}[/tex] = 11
To under the exponent you have to [tex]\sqrt[/tex] it.
[tex]\sqrt{b_{2}}[/tex] = [tex]\sqrt{11}[/tex]
[tex]5^{2} + 3.32^{2} = 6^{2}[/tex]
B = 3.31662479
rounded to 3.32
Check your work :
[tex]5^{2} + 3.32^{2} = 6^{2}[/tex]
