In this exercise we have to use the knowledge of polygon areas to calculate the area of each of the informed objects, so we have to:
1) [tex]h = 19.1 in[/tex]
2) [tex]a = 6.7 ft[/tex]
3) [tex]e = 2.3 m[/tex]
4) [tex]y = 9.8 cm[/tex]
5) [tex]o = 71.6 ft[/tex]
6) [tex]e = 15.3 in[/tex]
7) [tex]y = 41.5 m[/tex]
8) [tex]o = 13.7 cm[/tex]
9) [tex]p = 18.5 ft[/tex]
10) [tex]s = 25.8 in[/tex]
11) [tex]b = 61.3 m[/tex]
12) [tex]n = 6.2 cm[/tex]
Then each of the figures will have its own area formula that corresponds to:
1) For the rectangle we find that:
[tex]14/11 = h/15\\h = 19.1 in[/tex]
2) For the rectangle we find that:
[tex]5/a = 9/12\\a = 6.7 ft[/tex]
3)For the rectangle we find that:
[tex]3.7/6.5 = e/4.0\\e = 2.3 m[/tex]
4) For the triangle we find that:
[tex]10/8 = s/13\\s = 16.3 cm\\6/8 = y/13\\y = 9.8 cm[/tex]
5) For the triangle we find that:
[tex]n/70 = 53/88\\n = 42.2 ft\\o/70 = 90/88\\o = 71.6 ft[/tex]
6) For the triangle we find that:
[tex]t/9.1 = 11.2/5.7\\t = 17.9 in\\e/9.1 = 9.6/5.7\\e = 15.3 in[/tex]
7) For the triangle we find that:
[tex]u/48 = 43/74\\u = 27.9 m\\y/48 = 64/74\\y = 41.5 m[/tex]
8) For the triangle we find that:
[tex]6.2/11.8 = t/10.1\\t = 5.3 cm\\o/10.1 = 16.0/11.8\\o = 13.7 cm[/tex]
9) For the triangle we find that:
[tex]30/p = 13/8\\p = 18.5 ft[/tex]
10) For the trapezoid we find that:
[tex]20/s = 12/15.5\\s = 25.8 in[/tex]
11)For the triangle we find that:
[tex]l/46 = 125/75\\l = 76.7 m\\b/46 = 100/75\\b = 61.3 m[/tex]
12)For the triangle we find that:
[tex]5.1/4.3 = r/9.8\\r = 11.6 cm\\n/9.8 = 2.7/4.3\\n = 6.2 cm[/tex]
See more about areas at brainly.com/question/1631786
