Since you’re working with pressures and volumes, you need to use the gas law that relates the two. This would be Boyle’s law (P1V1 = P2T2). If we say that P1 is 5.80 atm and V1 is 4.44 L (notice that we kept those numbers together), and that V2 is 6.82 L, then P2 is what we’re looking for. Substituting these in:
P1V1 = P2V2
(5.80 atm)(4.44 L) = P2(6.82 L)
P2 = 3.78 atm
The sample will have a volume of 6.82 L at a pressure of 3.78 atm.
Hope this helps!
