Answer:
[tex]The\,\,answer\,\,for\,\,the\,\,question\,\,is\,\,(a)2,\,\,(b)6,\,\,(c)0[/tex]
Step-by-step explanation:
[tex]f(x)=\frac{x}{3} -1\\g(x)=2x-5\\\\a)f(6)+g(3)=(\frac{6}{3} -1)+(2*3-5)=2\\\\b)g^{-1}(x)=\frac{x+5}{2}\\ g^{-1}(7)=\frac{7+5}{2}=6\\\\c)f^{-1}(x)=3(x+1)\\f^{-1}(1)=3(1+1)=6\\g^{-1}(7)-f^{-1}(1)=6-6=0[/tex]
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