Answer:
[tex]The\,\,equation\,\,will\,\,be\,\,2x+y=8[/tex]
Step-by-step explanation:
Let, A=(3,2)
B=(-1,10)
So, The equation will be
[tex]\frac{x-x_{1} }{x_{1} -x_{2} } =\frac{y-y_{1} }{y_{1} -y_{2} } \\=>\frac{x-3 }{3-(-1) } =\frac{y-2 }{2-10} \\=>\frac{x-3 }{4} =\frac{y-2 }{-8}\\=>-8x+24=4y-8\\=>8x+4y=32\\=>2x+y=8[/tex]
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Answer:
y = - 2x + 8
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (3, 2 ) and (x₂, y₂ ) = (- 1, 10 )
m = [tex]\frac{10-2}{-1-3}[/tex] = [tex]\frac{8}{-4}[/tex] = - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 2 )
2 = - 6 + c ⇒ c = 2 + 6 = 8
y = - 2x + 8 ← equation of line
