For what values of x and y are the two triangles congruent by HL?

Answer:
y = 4 and x = 11
Step-by-step explanation:
x = y + 7 Substitute the first equation into the second equation and
solve for y
x + 1 = 3y
y + 7 + 1 = 3y
8 = 2y
4 = y x = y + 7
x = 4 + 7
x = 11