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Brenda wants to move a 30.0 kg table. She applies a force of 420 N. Under these conditions, the table initially moves with an acceleration of 4.80 m/s²

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onyebuchinnaji

The frictional force on the table when the given force is applied is 276 N.

The given parameters;

  • mass of the table, m = 30 kg
  • force applied by Brenda, F = 420 N
  • acceleration of the table, a = 4.8 m/s²

The frictional force on the table when the given force is applied is calculated as follows;

[tex]F - F_f = ma\\\\F_f = F- ma\\\\F_f = 420 - 30(4.8)\\\\F_f = 420 - 144\\\\F_f = 276 \ N[/tex]

Thus, the frictional force on the table when the given force is applied is 276 N.

"Your question is not complete it seems to be missing the following information";

Brenda wants to move a 30.0 kg table. She applies a force of 420 N. Under these conditions, the table initially moves with an acceleration of 4.80 m/s². Find the frictional force between the table and the floor when the force is applied.

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