Answer:
The surface area of the new cone is 240π inches² ⇒ answer D
Step-by-step explanation:
If the two cones are similar, then:
1. t1/t2=l1/l2=constant ratio
2. S.A1/S.A2=(R1/R2)^2
3. V1/V2=(R1/R2)3
The surface area of a right circular cone is 15π inches²
The cone is enlarged by multiplying both the radius of the base and the slant height by 4
The two cons are similar
R1/R2=1/4
The surface area of a right circular cone is 15π inches²
S.A1/S.A2=(R1/R2)^2
SO
15π/S.A2=(1/4)^2
15π/S.A2=1/16
By using cross multiplication:
15πX16=S.A2X1
240π=S.A2
The surface area of the enlarged cone = 240π inches²
The surface area of the new cone is 240π inches²
HOPE THAT HELPS!!
