The length of a rectangle is increasing at a rate of 7 cm/s and its width is increasing at a rate of 3 cm/s. When the length is 9 cm and the width is 7 cm, how fast is the area of the rectangle increasing?

Respuesta :

Answer:

76cm/s

Step-by-step explanation:

Let the length = L

width = W

A = LW

[tex]\frac{dL}{dt} = 7 cm/s[/tex]        (the rate at which the length is changing)

[tex]\frac{dW}{dt} = 3cm/s[/tex]       ( the rate at which the width is changing)  

[tex]\frac{dA}{dt} = L(\frac{dW}{dt} + W(\frac{dL}{dt} )[/tex]      Product Rule

[tex]\frac{dA}{dt} = 9(3) + 7(7)[/tex]

[tex]\frac{dA}{dt} = 27 + 49[/tex]

[tex]\frac{dA}{dt} = 76 cm/s[/tex]