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Calculate the theoretical yield in grams of All3, aluminum iodide, from the complete reaction of
113 grams l2 according to the following balanced chemical equation:
2 Al(s) + 3 I2(s) ---> 2 All3(s)

Respuesta :

Eduard22sly

The theoretical yield of AlI₃ obtained from the reaction is 121 g

We'll begin by calculating the mass of I₂ that reacted and the mass of AlI₃ produced from the balanced equation. This can be obtained as follow:

2Al + 3I₂ —> 2AlI₃

Molar mas of I₂ = 2 × 127 = 254 g/mol

Mass of I₂ from the balanced equation = 3 × 254 = 762 g

Molar mass of AlI₃ = 27 + (3 × 127) = 408 g/mol

Mass of AlI₃ from the balanced equation = 2 × 408 = 816 g

SUMMARY

From the balanced equation above,

762 g of I₂ reacted to produce 816 g of AlI₃

  • With the above information, we can obtain the theoretical yield of AlI₃ by the reaction of 113 g of I₂.

From the balanced equation above,

,762 g of I₂ reacted to produce 816 g of AlI₃

Therefore,

113 g of I₂ will react to produce = (113 × 816)/762 = 121 g of AlI₃

Thus, the theoretical yield of AlI₃ is 121 g

Learn more: https://brainly.com/question/4083269

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