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If an object is initially traveling at a velocity of 6 ms-1, then decelerates for 2 seconds, at which point its velocity is 2 ms-1, what is the acceleration of the object?

Respuesta :

sqdancefan

Answer:

  -2 m/s²

Explanation:

The relevant relation is ...

  acceleration = (change in velocity)/time

  = (2 m/s - 6 m/s)/(2 s) = -4/2 m/s² = -2 m/s²

The acceleration of the object is -2 m/s².

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf a= -2 \ m/s^2 }}[/tex]

Explanation:

We are asked to find the acceleration of an object. Acceleration is the rate of change of velocity with respect to time.

It is the change in velocity over time.

[tex]a= \frac{v_f-v_i}{t}[/tex]

The object is originally traveling at 6 meters per second, then it decelerates to 2 meters per second in 2 seconds.

  • [tex]v_f[/tex]= 2 m/s
  • [tex]v_i[/tex]= 6 m/s
  • t= 2 s

Substitute the values into the formula.

[tex]a= \frac{2 \ m/s- 6 \ m/s }{2 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{-4 \ m/s }{2 \ s }[/tex]

Divide.

[tex]a= -2 m/s/s[/tex]

[tex]a= -2 \ m/s^2[/tex]

The acceleration of the object is -2 meters per second squared.

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