Help homework due soon!!!

Solving a word problem using a system of linear equations:

Jose the trainer has two solo workout plans that he offers his clients: Plan A and Plan B. Each client does either one or the other (not both). On Monday there
were 4 clients who did Plan A and 8 who did Plan B. On Tuesday there were 2 clients who did Plan A and 3 who did Plan B. Jose trained his Monday clients for a
total of 9 hours and his Tuesday clients for a total of 4 hours. How long does each of the workout plans last?

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MrRoyal MrRoyal · Answer 1 · 2021-11-26T11:45:37+01:00

The plans are illustrations of system of linear equations

Plan A lasts for 1 and a half hour, while plan B lasts for 1/3 hour

Let A represent plan A, and B represents plan B

On Monday, we have:

4A + 8B = 9

On Tuesday, we have:

2A + 3B = 4

Multiply the second equation by 2

2 * (2A + 3B = 4)

4A + 6B = 8

Subtract this equation from the first equation.

So, we have:

4A - 4A + 8B - 6B = 9 - 8

3B = 1

Divide both sides by 3

[tex]\mathbf{B = \frac 13}[/tex]

Substitute 1/3 for B in 2A + 3B = 4

[tex]\mathbf{2A + 3 \times \frac 13 = 4}[/tex]

2A + 1 = 4

Subtract 1 from both sides

2A = 3

Divide both sides by 2

[tex]\mathbf{A = 1\frac 12}[/tex]

This means that:

Plan A lasts for 1 and a half hour, while plan B lasts for 1/3 hour

Read more about linear equations at:

https://brainly.com/question/11897796