Answer:
1. 20 km
2. 0.5 hours
3. 40 km
4. 1.5 hours
5. A, 40 km/hr
6. 80 km/hr, 40 km/hr
Step-by-step explanation:
2. The lines of Car A and Car B at 0.5 hours, meaning the cars have been traveling for 0.5 hours before they met.
1. From 0 hours to 0.5 hours, Car A traveled from 20 km to 40 km. The distance traveled before Car A met Car B was 40 km - 20 km = 20 km.
3. Cars A and B travel at the same speed starting at the 0.5 hour, 40 km point. They are traveling at the same speed from 0.5 hours to 1.5 hours since they share the same line and therefore the same slope. From the point at which Cars A and B met, they traveled from 40 km to 80 km. They traveled at the same speed for 80 km - 40 km = 40 km.
4. Both cars reached point C at the same time of 1.5 hours.
5. Car A had constant speed sicne the lines "Car A" and "Cars A and B" had the same slope. The speed is equal to the slope of the line: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{80-20}{1.5-0} = 40 km/hr[/tex]
6.
First speed: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{40-0}{0.5-0} = 80 km/hr[/tex]
Second speed: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{80-40}{1.5-0.5} = 40 km/hr[/tex]
