Answer:
[tex]F = ( \frac{9}{5}C ) + 32[/tex]
with F = xF and C = xC
=> f(x) = (9/5)x + 32
I'm sorry I can't mark the degree symbol
Step-by-step explanation:
[tex]f(x) = \frac{5}{9}(x-32) \\xC = \frac{5}{9}(xF-32) \\xC * \frac{9}{5} = \frac{5}{9}(xF-32) * \frac{9}{5} \\xC * \frac{9}{5} + 32 = xF - 32 + 32 \\\\xC * \frac{9}{5} + 32 = xF[/tex]