The amount of work done by a hammer thrower if an 8.0 kg hammer attached to a 1.3 m long rope is rotated horizontally above the thrower's head is 2450 Joules.
Given that an 8.0 kg hammer is attached to a 1.3 m long rope is rotated horizontally above the thrower's head. The hammer thrower holds the rope with a tension of 300 N.
The amount of Work done by the hammer thrower will be the product of Force (tension) and the circular distance ( circumference ).
Circumference = 2Ï€r
Where the radius of the circle will be the length of the attached rope which is 1.3 m. Substitute it into the formula above.
Circumference = 2 x 3.143 x 1.3
Circumference = 8.168 m
Work done = tension x Circumference
Work done = 300 x 8.168
Work done = 2450.4 Joule Â
Therefore, the amount of work done by a hammer thrower if an 8.0 kg hammer attached to a 1.3 m long rope is rotated horizontally above the thrower's head is 2450 Joules.
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