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Alberto has $2.25 in dimes and nickels in his pocket. He has nine more nickels than dimes. How many of each type of coin does he have?

I really need help!

Respuesta :

There is 12 dimes and 21 nickels
kapoorprachi783

Alberto has 12 Dimes and 21 Nickels in his pocket.

How many of each type of coin does he have?

Dimes value = 0.10$

Nickels value = 0.05$

Let d = number of dimes = 0.10d

Let d+9 = number of nickels = 0.05(d + 9)

Value of the Dimes + Value of the Nickels = total value of the coins

Write the equation:

0.10d + 0.05(d + 9) = 2.25

Distribute:

0.10d + 0.05d + 0.45 = 2.25

0.15d + 0.45 = 2.25

Subtract 0.45 from each side:

0.15d = 1.80

Divide to find the number of dimes.

d = 12

The number of nickels is d +9 = 12 + 9 = 21

Alberto has $2.25 in dimes and nickels in his pocket. He has 12 Dimes and 21 Nickels in his pocket.

Learn more about problem-solving here: brainly.com/question/23945932

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