Respuesta :
Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:
1. See attachment to this answer
2. a = 3.63 m/[tex]s^{2}[/tex]
3. μ = 0.36
Friction is an oppositional force between the surfaces of two bodies in contact, and tries to limit the motion of one body over the other. It is dependent on the nature of the surfaces in contact.
From the given question;
1. The free body diagram for this question is herewith attached to this answer.
Given that: [tex]F_{1}[/tex] = 50 N, [tex]F_{2}[/tex] = 15 N, [tex]F_{3}[/tex] = 6 N, and m = 8 kg.
2. The acceleration of the body can be determined by:
F = ma
where F is the total force acting on the body, m is the mass of the body and a is its acceleration.
So that;
a = [tex]\frac{F}{m}[/tex]
The total force on the body is;
F = [tex]F_{1}[/tex] - ([tex]F_{2}[/tex] + [tex]F_{3}[/tex])
= 50 - (15 + 6)
= 50 - 21
F = 29 N
Then;
a = [tex]\frac{29}{8}[/tex]
= 3.625
a = 3.63 m/[tex]s^{2}[/tex]
The acceleration of the body is 3.63 m/[tex]s^{2}[/tex].
3. The coefficient of limiting friction (μ) between the surfaces is:
μ = [tex]\frac{Force}{Reaction}[/tex]
Force = 29 N
Reaction = mg
= 8 x 10
= 80 N
μ = [tex]\frac{29}{80}[/tex]
= 0.3625
μ = 0.36
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Answer:
Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:
1. See attachment to this answer
2. a = 3.63 m/
3. μ = 0.36
Explanation: