Answer:
Force = mass × acceleration
[tex]{ \boxed{ \rm{F = ma}}}[/tex]
• For the first case;
[tex]{ \tt{F = 18m}}[/tex]
• For the second case;
[tex]{ \tt{3F = \frac{1}{2} m \times a}} \\ \\ { \tt{F = \frac{1}{6}m \times \frac{1}{3}a }}[/tex]
Then equate the equations:
[tex]{ \tt{18m = \frac{1}{6} m \times \frac{1}{3}a }} \\ \\ { \tt{18 = \frac{1}{3} ( \frac{1}{2} \times a)}} \\ \\ { \tt{54 = \frac{a}{2} }} \\ \\ { \boxed{ \mathfrak{answer{ : \rm {a = 98 \: m {s}^{ - 1} }}}}}[/tex]