The rate of change of velocity with respect to time is known as acceleration.
(a). After 10 second, rock will reach at its highest point.
(b). After 20.1875 second, rock fall back onto the moon surface.
Given data are, initial velocity(u) = 16 m/s , acceleration[tex](g)=1.6 m/s^{2}[/tex]
(a)Relation between initial velocity (u) and final velocity(v) and acceleration,
[tex]v = u - gt[/tex]
When rock reaches at its highest point. Then velocity (v) = 0
Substituting all values in above equation.
[tex]0 = 16 - (1.6)t[/tex]
[tex]t = 16/1.6[/tex]
[tex]t = 10 second.[/tex]
(b) Since, Astronaut Bob is standing on a platform 3 meters above the moon's surface .
So, time taken by rock to fall back onto moon surface is ,
[tex]t = 10 + 10 + 3/16[/tex]
t = 20.1875 second.
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