In ΔABC and ΔDEC,
AC = CE (Given)
∠B = ∠D (Given)
∠ACB = ∠DCE (Vertically Opposite Angles)
∴ ΔABC ≅ ΔDEC (By AAS Criteria)
Option C is correct
I had named the triangles to make the calculation easier...It is in the clip I attached.
Hope it helps you
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