Respuesta :

tanmayakumarp3

Answer:

[tex] {10cm}^{2} [/tex]

Step-by-step explanation:

Given,

Sum of parallel sides of the trapezium = 10 cm

Distance between or Height of the trapezium = 2 cm

As we know,

Area of a trapezium

[tex] = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height[/tex]

Therefore,

Area of the given trapezium will be,

[tex] = \frac{1}{2} \times 10 \: cm \times 2 \: cm[/tex]

  • (On Simplification )

= 1 × 10 cm × 1 cm

  • (On multiplying)

[tex] = 10 {cm}^{2} [/tex]

Hence,

The Area of the trapezium is 10 sq.cm (Ans)

Given :

  • The parallel sides of a trapezium are 2 cm apart and their sum is 10 cm.

To Find :

  • Its area.

Solution :

We know that,

[tex]{ \qquad \: \pmb{ \dfrac{1}{2} \times (sum \: of \: the \: parallel \: sides) \times height} = \pmb{Area_{(trapezium)}}}[/tex]

Now, Substituting the given values in the formula :

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 10\: \times 2 \: = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 20 = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{20}{2} = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ 10 = {Area_{(trapezium)}}}}}[/tex]

⠀

Hence,

  • The area of the trapezium = 10 cm² .

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