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A balloon contains 0.76 mol O2, 0.18 mol Ne, 0.031 mol Xe and 0.026 mol CO2 at 749 mm Hg. What is the partial pressure of Ne

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Answer:

ans given below

Explanation:

To keep simplicity, let's assume these gases behave ideally so we can use the equations for ideal gas. One of these equation is the Raoult's Law written below.

P* = xP

This is another form of the Raoult's Law where x is the mole fraction. Let's find x for O2.

x = 0.18/(0.76+0.18+0.031+0.026) = 0.1805

Partial Pressure = (0.1805)(749 mmHg) = 135.23 mmHg

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